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9x^{2}-\left(9y^{2}+6yz+z^{2}\right)
Rewrite as difference of two terms.
\left(3x\right)^{2}-\left(3y+z\right)^{2}
Rewrite the terms as squares.
\left(3x-3y-z\right)\left(3x+3y+z\right)
The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).