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\left(-2+3x-y\right)\left(-2+3x+y\right)
Rewrite 9x^{2}-12x+4-y^{2} as \left(-2+3x\right)^{2}-y^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(3x-y-2\right)\left(3x+y-2\right)
Reorder the terms.