Solve for b
b=-9x+\frac{8}{x}
x\neq 0
Solve for x
x=\frac{\sqrt{b^{2}+288}-b}{18}
x=\frac{-\sqrt{b^{2}+288}-b}{18}
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bx-8=-9x^{2}
Subtract 9x^{2} from both sides. Anything subtracted from zero gives its negation.
bx=-9x^{2}+8
Add 8 to both sides.
xb=8-9x^{2}
The equation is in standard form.
\frac{xb}{x}=\frac{8-9x^{2}}{x}
Divide both sides by x.
b=\frac{8-9x^{2}}{x}
Dividing by x undoes the multiplication by x.
b=-9x+\frac{8}{x}
Divide -9x^{2}+8 by x.
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