Solve 9x^2+3y=1

$$9 x ^ { 2 } + 3 y = 1$$

Solve for y

$$y=\frac{1}{3}-3x^{2}$$

Steps for Solving Linear Equation

Subtract 9x^{2} from both sides.

$$3y=1-9x^{2}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{1-9x^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{1-9x^{2}}{3}$$

Divide -9x^{2}+1 by 3.

$$y=\frac{1}{3}-3x^{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{1-3y}}{3}$$

$$x=\frac{\sqrt{1-3y}}{3}$$

Solve for x

$$x=\frac{\sqrt{1-3y}}{3}$$

$$x=-\frac{\sqrt{1-3y}}{3}\text{, }y\leq \frac{1}{3}$$