Solve 9x^2+1/9x^2-2

$$9 x ^ { 2 } + \frac { 1 } { 9 x ^ { 2 } } - 2$$

Evaluate

$$\frac{\left(9x-\frac{1}{x}\right)^{2}}{9}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 9x^{2}-2 times \frac{9x^{2}}{9x^{2}}.

$$\frac{\left(9x^{2}-2\right)\times 9x^{2}}{9x^{2}}+\frac{1}{9x^{2}}$$

Since \frac{\left(9x^{2}-2\right)\times 9x^{2}}{9x^{2}} and \frac{1}{9x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\left(9x^{2}-2\right)\times 9x^{2}+1}{9x^{2}}$$

Do the multiplications in \left(9x^{2}-2\right)\times 9x^{2}+1.

$$\frac{81x^{4}-18x^{2}+1}{9x^{2}}$$

Factor

$$\frac{\left(9x^{2}-1\right)^{2}}{9x^{2}}$$