Solve for c (complex solution)
\left\{\begin{matrix}c=-\frac{-9x+d-b}{x}\text{, }&x\neq 0\\c\in \mathrm{C}\text{, }&x=0\text{ and }b=d\end{matrix}\right.
Solve for c
\left\{\begin{matrix}c=-\frac{-9x+d-b}{x}\text{, }&x\neq 0\\c\in \mathrm{R}\text{, }&x=0\text{ and }b=d\end{matrix}\right.
Solve for b
b=cx-9x+d
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cx+d=9x+b
Swap sides so that all variable terms are on the left hand side.
cx=9x+b-d
Subtract d from both sides.
xc=9x+b-d
The equation is in standard form.
\frac{xc}{x}=\frac{9x+b-d}{x}
Divide both sides by x.
c=\frac{9x+b-d}{x}
Dividing by x undoes the multiplication by x.
cx+d=9x+b
Swap sides so that all variable terms are on the left hand side.
cx=9x+b-d
Subtract d from both sides.
xc=9x+b-d
The equation is in standard form.
\frac{xc}{x}=\frac{9x+b-d}{x}
Divide both sides by x.
c=\frac{9x+b-d}{x}
Dividing by x undoes the multiplication by x.
b=cx+d-9x
Subtract 9x from both sides.
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