Solve for x
x=-\frac{y}{3}-\frac{2}{9}
Solve for y
y=-3x-\frac{2}{3}
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9x=-2-3y
Subtract 3y from both sides.
9x=-3y-2
The equation is in standard form.
\frac{9x}{9}=\frac{-3y-2}{9}
Divide both sides by 9.
x=\frac{-3y-2}{9}
Dividing by 9 undoes the multiplication by 9.
x=-\frac{y}{3}-\frac{2}{9}
Divide -2-3y by 9.
3y=-2-9x
Subtract 9x from both sides.
3y=-9x-2
The equation is in standard form.
\frac{3y}{3}=\frac{-9x-2}{3}
Divide both sides by 3.
y=\frac{-9x-2}{3}
Dividing by 3 undoes the multiplication by 3.
y=-3x-\frac{2}{3}
Divide -2-9x by 3.
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