Solve for x
x=\frac{y+398}{9}
Solve for y
y=9x-398
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9x-y=400-2
Subtract 2 from both sides.
9x-y=398
Subtract 2 from 400 to get 398.
9x=398+y
Add y to both sides.
9x=y+398
The equation is in standard form.
\frac{9x}{9}=\frac{y+398}{9}
Divide both sides by 9.
x=\frac{y+398}{9}
Dividing by 9 undoes the multiplication by 9.
2-y=400-9x
Subtract 9x from both sides.
-y=400-9x-2
Subtract 2 from both sides.
-y=398-9x
Subtract 2 from 400 to get 398.
\frac{-y}{-1}=\frac{398-9x}{-1}
Divide both sides by -1.
y=\frac{398-9x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=9x-398
Divide 398-9x by -1.
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