Solve 9x+15+x=23x-13quadb)

$$9 x + 15 + x = 23 x - 13 \quad b )$$

Solve for b

$$b = -\frac{15}{13} = -1\frac{2}{13} = -1.1538461538461537$$

Steps for Solving Linear Equation

Combine 9x and x to get 10x.

$$10x+15=23x-13b$$

Swap sides so that all variable terms are on the left hand side.

$$23x-13b=10x+15$$

Subtract 23x from both sides.

$$-13b=10x+15-23x$$

Combine 10x and -23x to get -13x.

$$-13b=-13x+15$$

The equation is in standard form.

$$-13b=15-13x$$

Divide both sides by -13.

$$\frac{-13b}{-13}=\frac{15-13x}{-13}$$

Dividing by -13 undoes the multiplication by -13.

$$b=\frac{15-13x}{-13}$$

Divide -13x+15 by -13.

$$b=x-\frac{15}{13}$$

Solve for x

$$x = \frac{15}{13} = 1\frac{2}{13} = 1.1538461538461537$$

Steps for Solving Linear Equation

Combine 9x and x to get 10x.

$$10x+15=23x-13b$$

Subtract 23x from both sides.

$$10x+15-23x=-13b$$

Combine 10x and -23x to get -13x.

$$-13x+15=-13b$$

Subtract 15 from both sides.

$$-13x=-13b-15$$

Divide both sides by -13.

$$\frac{-13x}{-13}=\frac{-13b-15}{-13}$$

Dividing by -13 undoes the multiplication by -13.

$$x=\frac{-13b-15}{-13}$$

Divide -13b-15 by -13.

$$x=b+\frac{15}{13}$$