Solve 9x+12leq10x-8

$$9 x + 12 \leq 10 x - 8$$

Solve for x

$$x\geq 20$$

Solution Steps

Subtract 10x from both sides.

$$9x+12-10x\leq -8$$

Combine 9x and -10x to get -x.

$$-x+12\leq -8$$

Subtract 12 from both sides.

$$-x\leq -8-12$$

Subtract 12 from -8 to get -20.

$$-x\leq -20$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x\geq \frac{-20}{-1}$$

Fraction \frac{-20}{-1} can be simplified to 20 by removing the negative sign from both the numerator and the denominator.

$$x\geq 20$$