Solve 9x+10x^2=

$$9 x + 10 x ^ { 2 } =$$

Factor

$$x\left(10x+9\right)$$

Solution Steps

Factor out x.

$$x\left(9+10x\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$10x^{2}+9x=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-9±\sqrt{9^{2}}}{2\times 10}$$

Take the square root of 9^{2}.

$$x=\frac{-9±9}{2\times 10}$$

Multiply 2 times 10.

$$x=\frac{-9±9}{20}$$

Now solve the equation x=\frac{-9±9}{20} when ± is plus. Add -9 to 9.

$$x=\frac{0}{20}$$

Divide 0 by 20.

$$x=0$$

Now solve the equation x=\frac{-9±9}{20} when ± is minus. Subtract 9 from -9.

$$x=-\frac{18}{20}$$

Reduce the fraction \frac{-18}{20} to lowest terms by extracting and canceling out 2.

$$x=-\frac{9}{10}$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 0 for x_{1} and -\frac{9}{10} for x_{2}.

$$10x^{2}+9x=10x\left(x-\left(-\frac{9}{10}\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$10x^{2}+9x=10x\left(x+\frac{9}{10}\right)$$

Add \frac{9}{10} to x by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

$$10x^{2}+9x=10x\times \frac{10x+9}{10}$$

Cancel out 10, the greatest common factor in 10 and 10.

$$10x^{2}+9x=x\left(10x+9\right)$$

Evaluate

$$x\left(10x+9\right)$$