Solve 9x+3/2y=14

$$9 x + \frac { 3 } { 2 } y = 14$$

Solve for x

$$x=-\frac{y}{6}+\frac{14}{9}$$

Steps for Solving Linear Equation

Subtract \frac{3}{2}y from both sides.

$$9x=14-\frac{3}{2}y$$

The equation is in standard form.

$$9x=-\frac{3y}{2}+14$$

Divide both sides by 9.

$$\frac{9x}{9}=\frac{-\frac{3y}{2}+14}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x=\frac{-\frac{3y}{2}+14}{9}$$

Divide 14-\frac{3y}{2} by 9.

$$x=-\frac{y}{6}+\frac{14}{9}$$

Solve for y

$$y=\frac{28}{3}-6x$$

Steps for Solving Linear Equation

Subtract 9x from both sides.

$$\frac{3}{2}y=14-9x$$

Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}y}{\frac{3}{2}}=\frac{14-9x}{\frac{3}{2}}$$

Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.

$$y=\frac{14-9x}{\frac{3}{2}}$$

Divide 14-9x by \frac{3}{2} by multiplying 14-9x by the reciprocal of \frac{3}{2}.

$$y=\frac{28}{3}-6x$$