Solve 9m+23m+1/5m=

$$9 m + 23 m + \frac { 1 } { 5 } m =$$

Evaluate

$$\frac{161m}{5}$$

Solution Steps

Combine 9m and 23m to get 32m.

$$32m+\frac{1}{5}m$$

Combine 32m and \frac{1}{5}m to get \frac{161}{5}m.

$$\frac{161}{5}m$$

Differentiate w.r.t. m

$$\frac{161}{5} = 32\frac{1}{5} = 32.2$$

Steps Using Definition of a Derivative

Combine 9m and 23m to get 32m.

$$\frac{\mathrm{d}}{\mathrm{d}m}(32m+\frac{1}{5}m)$$

Combine 32m and \frac{1}{5}m to get \frac{161}{5}m.

$$\frac{\mathrm{d}}{\mathrm{d}m}(\frac{161}{5}m)$$

The derivative of ax^{n} is nax^{n-1}.

$$\frac{161}{5}m^{1-1}$$

Subtract 1 from 1.

$$\frac{161}{5}m^{0}$$

For any term t except 0, t^{0}=1.

$$\frac{161}{5}\times 1$$

For any term t, t\times 1=t and 1t=t.

$$\frac{161}{5}$$