Solve 9hdiv2=3ahdiv6

$$9 h \div 2 = 3 a h \div 6$$

Solve for a

$$\left\{\begin{matrix}\\a=9\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&h=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 2,6.

$$3\times 9h=3ah$$

Multiply 3 and 9 to get 27.

$$27h=3ah$$

Swap sides so that all variable terms are on the left hand side.

$$3ah=27h$$

The equation is in standard form.

$$3ha=27h$$

Divide both sides by 3h.

$$\frac{3ha}{3h}=\frac{27h}{3h}$$

Dividing by 3h undoes the multiplication by 3h.

$$a=\frac{27h}{3h}$$

Divide 27h by 3h.

$$a=9$$

Solve for h

$$\left\{\begin{matrix}\\h=0\text{, }&\text{unconditionally}\\h\in \mathrm{R}\text{, }&a=9\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 2,6.

$$3\times 9h=3ah$$

Multiply 3 and 9 to get 27.

$$27h=3ah$$

Subtract 3ah from both sides.

$$27h-3ah=0$$

Combine all terms containing h.

$$\left(27-3a\right)h=0$$

Divide 0 by 27-3a.

$$h=0$$