Solve 9g03-(8g5-x)=2g

$$9 g 03 - ( 8 g 5 - x ) = 2 g$$

Solve for g

$$g=\frac{x+27g_{0}-8g_{5}}{2}$$

Steps for Solving Linear Equation

Multiply 9 and 3 to get 27.

$$27g_{0}-\left(8g_{5}-x\right)=2g$$

To find the opposite of 8g_{5}-x, find the opposite of each term.

$$27g_{0}-8g_{5}+x=2g$$

Swap sides so that all variable terms are on the left hand side.

$$2g=27g_{0}-8g_{5}+x$$

The equation is in standard form.

$$2g=x+27g_{0}-8g_{5}$$

Divide both sides by 2.

$$\frac{2g}{2}=\frac{x+27g_{0}-8g_{5}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$g=\frac{x+27g_{0}-8g_{5}}{2}$$

Divide 27g_{0}-8g_{5}+x by 2.

$$g=\frac{x}{2}+\frac{27g_{0}}{2}-4g_{5}$$

Solve for g_0

$$g_{0}=\frac{8g_{5}+2g-x}{27}$$

Steps for Solving Linear Equation

Multiply 9 and 3 to get 27.

$$27g_{0}-\left(8g_{5}-x\right)=2g$$

To find the opposite of 8g_{5}-x, find the opposite of each term.

$$27g_{0}-8g_{5}+x=2g$$

Add 8g_{5} to both sides.

$$27g_{0}+x=2g+8g_{5}$$

Subtract x from both sides.

$$27g_{0}=2g+8g_{5}-x$$

The equation is in standard form.

$$27g_{0}=8g_{5}+2g-x$$

Divide both sides by 27.

$$\frac{27g_{0}}{27}=\frac{8g_{5}+2g-x}{27}$$

Dividing by 27 undoes the multiplication by 27.

$$g_{0}=\frac{8g_{5}+2g-x}{27}$$