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\left(3b+c-7\right)\left(3b+c+7\right)
Rewrite 9b^{2}+6bc+c^{2}-49 as \left(3b+c\right)^{2}-7^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).