Solve for a
a=\frac{2b+c}{5}
Solve for b
b=\frac{5a-c}{2}
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9a-2b-4a=c
Subtract 4a from both sides.
5a-2b=c
Combine 9a and -4a to get 5a.
5a=c+2b
Add 2b to both sides.
5a=2b+c
The equation is in standard form.
\frac{5a}{5}=\frac{2b+c}{5}
Divide both sides by 5.
a=\frac{2b+c}{5}
Dividing by 5 undoes the multiplication by 5.
-2b=c+4a-9a
Subtract 9a from both sides.
-2b=c-5a
Combine 4a and -9a to get -5a.
\frac{-2b}{-2}=\frac{c-5a}{-2}
Divide both sides by -2.
b=\frac{c-5a}{-2}
Dividing by -2 undoes the multiplication by -2.
b=\frac{5a-c}{2}
Divide c-5a by -2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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