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\left(3a-4c-1-2b\right)\left(3a-4c+1+2b\right)
Rewrite 9a^{2}-4b^{2}+16c^{2}-1-4b-24ac as \left(3a-4c\right)^{2}-\left(1+2b\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\left(3a-2b-4c-1\right)\left(3a+2b-4c+1\right)
Reorder the terms.