Solve for A
A=-\frac{B}{3}-\frac{4d}{9}-\frac{19C}{9}-\frac{40}{9}
Solve for B
B=-\frac{4d}{3}-\frac{19C}{3}-3A-\frac{40}{3}
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9A+19C+4d=-40-3B
Subtract 3B from both sides.
9A+4d=-40-3B-19C
Subtract 19C from both sides.
9A=-40-3B-19C-4d
Subtract 4d from both sides.
9A=-3B-19C-4d-40
The equation is in standard form.
\frac{9A}{9}=\frac{-3B-19C-4d-40}{9}
Divide both sides by 9.
A=\frac{-3B-19C-4d-40}{9}
Dividing by 9 undoes the multiplication by 9.
A=-\frac{B}{3}-\frac{4d}{9}-\frac{19C}{9}-\frac{40}{9}
Divide -40-3B-19C-4d by 9.
3B+19C+4d=-40-9A
Subtract 9A from both sides.
3B+4d=-40-9A-19C
Subtract 19C from both sides.
3B=-40-9A-19C-4d
Subtract 4d from both sides.
3B=-9A-19C-4d-40
The equation is in standard form.
\frac{3B}{3}=\frac{-9A-19C-4d-40}{3}
Divide both sides by 3.
B=\frac{-9A-19C-4d-40}{3}
Dividing by 3 undoes the multiplication by 3.
B=-\frac{4d}{3}-\frac{19C}{3}-3A-\frac{40}{3}
Divide -40-9A-19C-4d by 3.
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