Solve 9-xz=xpi/8+x

$$9 - x z = x \frac { \pi } { 8 } + x$$

Solve for x

$$x=\frac{72}{8z+\pi +8}$$

$$z\neq -\frac{\pi }{8}-1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8.

$$72-8xz=x\pi +8x$$

Subtract x\pi from both sides.

$$72-8xz-x\pi =8x$$

Subtract 8x from both sides.

$$72-8xz-x\pi -8x=0$$

Subtract 72 from both sides. Anything subtracted from zero gives its negation.

$$-8xz-x\pi -8x=-72$$

Combine all terms containing x.

$$\left(-8z-\pi -8\right)x=-72$$

Divide both sides by -8z-\pi -8.

$$\frac{\left(-8z-\pi -8\right)x}{-8z-\pi -8}=-\frac{72}{-8z-\pi -8}$$

Dividing by -8z-\pi -8 undoes the multiplication by -8z-\pi -8.

$$x=-\frac{72}{-8z-\pi -8}$$

Divide -72 by -8z-\pi -8.

$$x=\frac{72}{8z+\pi +8}$$

Solve for z

$$z=-\frac{\pi }{8}-1+\frac{9}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8.

$$72-8xz=x\pi +8x$$

Subtract 72 from both sides.

$$-8xz=x\pi +8x-72$$

The equation is in standard form.

$$\left(-8x\right)z=\pi x+8x-72$$

Divide both sides by -8x.

$$\frac{\left(-8x\right)z}{-8x}=\frac{\pi x+8x-72}{-8x}$$

Dividing by -8x undoes the multiplication by -8x.

$$z=\frac{\pi x+8x-72}{-8x}$$

Divide x\pi +8x-72 by -8x.

$$z=-\frac{\pi }{8}-1+\frac{9}{x}$$