Solve 9-51/6+41/12

$$9 - 5 \frac { 1 } { 6 } + 4 \frac { 1 } { 12 }$$

Evaluate

$$\frac{95}{12}\approx 7.916666667$$

Solution Steps

Multiply 5 and 6 to get 30.

$$9-\frac{30+1}{6}+\frac{4\times 12+1}{12}$$

Add 30 and 1 to get 31.

$$9-\frac{31}{6}+\frac{4\times 12+1}{12}$$

Convert 9 to fraction \frac{54}{6}.

$$\frac{54}{6}-\frac{31}{6}+\frac{4\times 12+1}{12}$$

Since \frac{54}{6} and \frac{31}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{54-31}{6}+\frac{4\times 12+1}{12}$$

Subtract 31 from 54 to get 23.

$$\frac{23}{6}+\frac{4\times 12+1}{12}$$

Multiply 4 and 12 to get 48.

$$\frac{23}{6}+\frac{48+1}{12}$$

Add 48 and 1 to get 49.

$$\frac{23}{6}+\frac{49}{12}$$

Least common multiple of 6 and 12 is 12. Convert \frac{23}{6} and \frac{49}{12} to fractions with denominator 12.

$$\frac{46}{12}+\frac{49}{12}$$

Since \frac{46}{12} and \frac{49}{12} have the same denominator, add them by adding their numerators.

$$\frac{46+49}{12}$$

Add 46 and 49 to get 95.

$$\frac{95}{12}$$

Factor

$$\frac{5 \cdot 19}{2 ^ {2} \cdot 3} = 7\frac{11}{12} = 7.916666666666667$$