Solve 9-51/10+41/12

$$9 - 5 \frac { 1 } { 10 } + 4 \frac { 1 } { 12 }$$

Evaluate

$$\frac{479}{60}\approx 7.983333333$$

Solution Steps

Multiply 5 and 10 to get 50.

$$9-\frac{50+1}{10}+\frac{4\times 12+1}{12}$$

Add 50 and 1 to get 51.

$$9-\frac{51}{10}+\frac{4\times 12+1}{12}$$

Convert 9 to fraction \frac{90}{10}.

$$\frac{90}{10}-\frac{51}{10}+\frac{4\times 12+1}{12}$$

Since \frac{90}{10} and \frac{51}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{90-51}{10}+\frac{4\times 12+1}{12}$$

Subtract 51 from 90 to get 39.

$$\frac{39}{10}+\frac{4\times 12+1}{12}$$

Multiply 4 and 12 to get 48.

$$\frac{39}{10}+\frac{48+1}{12}$$

Add 48 and 1 to get 49.

$$\frac{39}{10}+\frac{49}{12}$$

Least common multiple of 10 and 12 is 60. Convert \frac{39}{10} and \frac{49}{12} to fractions with denominator 60.

$$\frac{234}{60}+\frac{245}{60}$$

Since \frac{234}{60} and \frac{245}{60} have the same denominator, add them by adding their numerators.

$$\frac{234+245}{60}$$

Add 234 and 245 to get 479.

$$\frac{479}{60}$$

Factor

$$\frac{479}{2 ^ {2} \cdot 3 \cdot 5} = 7\frac{59}{60} = 7.983333333333333$$