Solve 9-3(x-4)+6(-6-x)=0

$$9 - 3 ( x - 4 ) + 6 ( - 6 - x ) = 0$$

Solve for x

$$x = -\frac{5}{3} = -1\frac{2}{3} \approx -1.666666667$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by x-4.

$$9-3x+12+6\left(-6-x\right)=0$$

Add 9 and 12 to get 21.

$$21-3x+6\left(-6-x\right)=0$$

Use the distributive property to multiply 6 by -6-x.

$$21-3x-36-6x=0$$

Subtract 36 from 21 to get -15.

$$-15-3x-6x=0$$

Combine -3x and -6x to get -9x.

$$-15-9x=0$$

Add 15 to both sides. Anything plus zero gives itself.

$$-9x=15$$

Divide both sides by -9.

$$x=\frac{15}{-9}$$

Reduce the fraction \frac{15}{-9} to lowest terms by extracting and canceling out 3.

$$x=-\frac{5}{3}$$