Solve 9-9/n^2j^2)(3/n)

$$9 - \frac { 9 } { n ^ { 2 } } j ^ { 2 } ) ( \frac { 3 } { n } )$$

Evaluate

$$-9\times \left(\frac{j}{n}\right)^{2}+9$$

Short Solution Steps

Express \frac{9}{n^{2}}j^{2} as a single fraction.

$$9-\frac{9j^{2}}{n^{2}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 9 times \frac{n^{2}}{n^{2}}.

$$\frac{9n^{2}}{n^{2}}-\frac{9j^{2}}{n^{2}}$$

Since \frac{9n^{2}}{n^{2}} and \frac{9j^{2}}{n^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9n^{2}-9j^{2}}{n^{2}}$$

Factor

$$\frac{9\left(n^{2}-j^{2}\right)}{n^{2}}$$