Solve 9-3/5+62/3(206/15)

$$9 - \frac { 3 } { 5 } + 6 \frac { 2 } { 3 } ( \frac { 206 } { 15 } )$$

Evaluate

$$\frac{4498}{45}\approx 99.955555556$$

Solution Steps

Convert 9 to fraction \frac{45}{5}.

$$\frac{45}{5}-\frac{3}{5}+\frac{6\times 3+2}{3}\times \frac{206}{15}$$

Since \frac{45}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{45-3}{5}+\frac{6\times 3+2}{3}\times \frac{206}{15}$$

Subtract 3 from 45 to get 42.

$$\frac{42}{5}+\frac{6\times 3+2}{3}\times \frac{206}{15}$$

Multiply 6 and 3 to get 18.

$$\frac{42}{5}+\frac{18+2}{3}\times \frac{206}{15}$$

Add 18 and 2 to get 20.

$$\frac{42}{5}+\frac{20}{3}\times \frac{206}{15}$$

Multiply \frac{20}{3} times \frac{206}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{42}{5}+\frac{20\times 206}{3\times 15}$$

Do the multiplications in the fraction \frac{20\times 206}{3\times 15}.

$$\frac{42}{5}+\frac{4120}{45}$$

Reduce the fraction \frac{4120}{45} to lowest terms by extracting and canceling out 5.

$$\frac{42}{5}+\frac{824}{9}$$

Least common multiple of 5 and 9 is 45. Convert \frac{42}{5} and \frac{824}{9} to fractions with denominator 45.

$$\frac{378}{45}+\frac{4120}{45}$$

Since \frac{378}{45} and \frac{4120}{45} have the same denominator, add them by adding their numerators.

$$\frac{378+4120}{45}$$

Add 378 and 4120 to get 4498.

$$\frac{4498}{45}$$

Factor

$$\frac{2 \cdot 13 \cdot 173}{3 ^ {2} \cdot 5} = 99\frac{43}{45} = 99.95555555555555$$