Solve 9(x/3+1)geq6

$$9 ( \frac { x } { 3 } + 1 ) \geq 6$$

Solve for x

$$x\geq -1$$

Solution Steps

Divide both sides by 9. Since 9 is positive, the inequality direction remains the same.

$$\frac{x}{3}+1\geq \frac{6}{9}$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{x}{3}+1\geq \frac{2}{3}$$

Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.

$$x+3\geq 2$$

Subtract 3 from both sides.

$$x\geq 2-3$$

Subtract 3 from 2 to get -1.

$$x\geq -1$$