Solve 9y^2-26x-9=0

$$9 { y }^{ 2 } -26x-9=0$$

Solve for x

$$x=\frac{9\left(y^{2}-1\right)}{26}$$

Steps for Solving Linear Equation

Subtract 9y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-26x-9=-9y^{2}$$

Add 9 to both sides.

$$-26x=-9y^{2}+9$$

The equation is in standard form.

$$-26x=9-9y^{2}$$

Divide both sides by -26.

$$\frac{-26x}{-26}=\frac{9-9y^{2}}{-26}$$

Dividing by -26 undoes the multiplication by -26.

$$x=\frac{9-9y^{2}}{-26}$$

Divide 9-9y^{2} by -26.

$$x=\frac{9y^{2}-9}{26}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{26x+9}}{3}$$

$$y=\frac{\sqrt{26x+9}}{3}$$

Solve for y

$$y=\frac{\sqrt{26x+9}}{3}$$

$$y=-\frac{\sqrt{26x+9}}{3}\text{, }x\geq -\frac{9}{26}$$