Solve for x
x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333
x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333
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x^{2}=\frac{16}{9}
Divide both sides by 9.
x^{2}-\frac{16}{9}=0
Subtract \frac{16}{9} from both sides.
9x^{2}-16=0
Multiply both sides by 9.
\left(3x-4\right)\left(3x+4\right)=0
Consider 9x^{2}-16. Rewrite 9x^{2}-16 as \left(3x\right)^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{4}{3} x=-\frac{4}{3}
To find equation solutions, solve 3x-4=0 and 3x+4=0.
x^{2}=\frac{16}{9}
Divide both sides by 9.
x=\frac{4}{3} x=-\frac{4}{3}
Take the square root of both sides of the equation.
x^{2}=\frac{16}{9}
Divide both sides by 9.
x^{2}-\frac{16}{9}=0
Subtract \frac{16}{9} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{16}{9}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{16}{9} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{16}{9}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{64}{9}}}{2}
Multiply -4 times -\frac{16}{9}.
x=\frac{0±\frac{8}{3}}{2}
Take the square root of \frac{64}{9}.
x=\frac{4}{3}
Now solve the equation x=\frac{0±\frac{8}{3}}{2} when ± is plus.
x=-\frac{4}{3}
Now solve the equation x=\frac{0±\frac{8}{3}}{2} when ± is minus.
x=\frac{4}{3} x=-\frac{4}{3}
The equation is now solved.
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Simultaneous equation
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Limits
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