Solve for x
x\in \left(-\frac{5}{3},\frac{5}{3}\right)
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x^{2}<\frac{25}{9}
Divide both sides by 9. Since 9 is positive, the inequality direction remains the same.
x^{2}<\left(\frac{5}{3}\right)^{2}
Calculate the square root of \frac{25}{9} and get \frac{5}{3}. Rewrite \frac{25}{9} as \left(\frac{5}{3}\right)^{2}.
|x|<\frac{5}{3}
Inequality holds for |x|<\frac{5}{3}.
x\in \left(-\frac{5}{3},\frac{5}{3}\right)
Rewrite |x|<\frac{5}{3} as x\in \left(-\frac{5}{3},\frac{5}{3}\right).
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