Solve for c
c=\frac{81}{2fh}
h\neq 0\text{ and }f\neq 0
Solve for f
f=\frac{81}{2ch}
h\neq 0\text{ and }c\neq 0
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9\times 90=20fch
Multiply both sides of the equation by 20.
810=20fch
Multiply 9 and 90 to get 810.
20fch=810
Swap sides so that all variable terms are on the left hand side.
20fhc=810
The equation is in standard form.
\frac{20fhc}{20fh}=\frac{810}{20fh}
Divide both sides by 20fh.
c=\frac{810}{20fh}
Dividing by 20fh undoes the multiplication by 20fh.
c=\frac{81}{2fh}
Divide 810 by 20fh.
9\times 90=20fch
Multiply both sides of the equation by 20.
810=20fch
Multiply 9 and 90 to get 810.
20fch=810
Swap sides so that all variable terms are on the left hand side.
20chf=810
The equation is in standard form.
\frac{20chf}{20ch}=\frac{810}{20ch}
Divide both sides by 20ch.
f=\frac{810}{20ch}
Dividing by 20ch undoes the multiplication by 20ch.
f=\frac{81}{2ch}
Divide 810 by 20ch.
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