Solve 9*3=H^2

$$9 \times 3 = H ^ { 2 }$$

Solve for H

$$H=3\sqrt{3}\approx 5.196152423$$

$$H=-3\sqrt{3}\approx -5.196152423$$

Steps by Finding Square Root

Multiply 9 and 3 to get 27.

$$27=H^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$H^{2}=27$$

Take the square root of both sides of the equation.

$$H=3\sqrt{3} H=-3\sqrt{3}$$

Steps Using the Quadratic Formula

Multiply 9 and 3 to get 27.

$$27=H^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$H^{2}=27$$

Subtract 27 from both sides.

$$H^{2}-27=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -27 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$H=\frac{0±\sqrt{0^{2}-4\left(-27\right)}}{2}$$

Square 0.

$$H=\frac{0±\sqrt{-4\left(-27\right)}}{2}$$

Multiply -4 times -27.

$$H=\frac{0±\sqrt{108}}{2}$$

Take the square root of 108.

$$H=\frac{0±6\sqrt{3}}{2}$$

Now solve the equation H=\frac{0±6\sqrt{3}}{2} when ± is plus.

$$H=3\sqrt{3}$$

Now solve the equation H=\frac{0±6\sqrt{3}}{2} when ± is minus.

$$H=-3\sqrt{3}$$

The equation is now solved.

$$H=3\sqrt{3} H=-3\sqrt{3}$$