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9\times 12^{n}=88
Use the rules of exponents and logarithms to solve the equation.
12^{n}=\frac{88}{9}
Divide both sides by 9.
\log(12^{n})=\log(\frac{88}{9})
Take the logarithm of both sides of the equation.
n\log(12)=\log(\frac{88}{9})
The logarithm of a number raised to a power is the power times the logarithm of the number.
n=\frac{\log(\frac{88}{9})}{\log(12)}
Divide both sides by \log(12).
n=\log_{12}\left(\frac{88}{9}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).