Solve 9*(-{left(2/3right)}^2-12*(-2/3)+3

$$9 \times (- { \left( \frac{ 2 }{ 3 } \right) }^{ 2 } -12 \times (- \frac{ 2 }{ 3 } )+3$$

Evaluate

$$95$$

Solution Steps

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$9\left(-\frac{4}{9}-12\left(-\frac{2}{3}\right)+3\right)$$

Express 12\left(-\frac{2}{3}\right) as a single fraction.

$$9\left(-\frac{4}{9}-\frac{12\left(-2\right)}{3}+3\right)$$

Multiply 12 and -2 to get -24.

$$9\left(-\frac{4}{9}-\frac{-24}{3}+3\right)$$

Divide -24 by 3 to get -8.

$$9\left(-\frac{4}{9}-\left(-8\right)+3\right)$$

The opposite of -8 is 8.

$$9\left(-\frac{4}{9}+8+3\right)$$

Convert 8 to fraction \frac{72}{9}.

$$9\left(-\frac{4}{9}+\frac{72}{9}+3\right)$$

Since -\frac{4}{9} and \frac{72}{9} have the same denominator, add them by adding their numerators.

$$9\left(\frac{-4+72}{9}+3\right)$$

Add -4 and 72 to get 68.

$$9\left(\frac{68}{9}+3\right)$$

Convert 3 to fraction \frac{27}{9}.

$$9\left(\frac{68}{9}+\frac{27}{9}\right)$$

Since \frac{68}{9} and \frac{27}{9} have the same denominator, add them by adding their numerators.

$$9\times \frac{68+27}{9}$$

Add 68 and 27 to get 95.

$$9\times \frac{95}{9}$$

Cancel out 9 and 9.

$$95$$

Factor

$$5\times 19$$