Solve 9*sin(53^circ)+9cos(53^circ)

$$9 \times \sin ( 53 ^ { \circ } ) +9 \cos ( 53 ^ { \circ } )$$

Evaluate

$$12.6040547987940708$$

Solution Steps

Evaluate trigonometric functions in the problem

$$9 \cdot 0.7986355100472928 + 9 \cdot 0.6018150231520484$$

Multiply 9 and 0.7986355100472928 to get 7.1877195904256352.

$$7.1877195904256352+9\times 0.6018150231520484$$

Multiply 9 and 0.6018150231520484 to get 5.4163352083684356.

$$7.1877195904256352+5.4163352083684356$$

Add 7.1877195904256352 and 5.4163352083684356 to get 12.6040547987940708.

$$12.6040547987940708$$

Factor

$$\frac{89 \cdot 13681 \cdot 319490113 \cdot 3 ^ {4}}{2 ^ {14} \cdot 5 ^ {16}} = 12\frac{1510136996985176}{2500000000000000} = 12.60405479879407$$