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\frac{9\times 3\sqrt{5}}{\sqrt{\frac{1\times 2+1}{2}}}
Factor 45=3^{2}\times 5. Rewrite the square root of the product \sqrt{3^{2}\times 5} as the product of square roots \sqrt{3^{2}}\sqrt{5}. Take the square root of 3^{2}.
\frac{27\sqrt{5}}{\sqrt{\frac{1\times 2+1}{2}}}
Multiply 9 and 3 to get 27.
\frac{27\sqrt{5}}{\sqrt{\frac{2+1}{2}}}
Multiply 1 and 2 to get 2.
\frac{27\sqrt{5}}{\sqrt{\frac{3}{2}}}
Add 2 and 1 to get 3.
\frac{27\sqrt{5}}{\frac{\sqrt{3}}{\sqrt{2}}}
Rewrite the square root of the division \sqrt{\frac{3}{2}} as the division of square roots \frac{\sqrt{3}}{\sqrt{2}}.
\frac{27\sqrt{5}}{\frac{\sqrt{3}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}}
Rationalize the denominator of \frac{\sqrt{3}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{27\sqrt{5}}{\frac{\sqrt{3}\sqrt{2}}{2}}
The square of \sqrt{2} is 2.
\frac{27\sqrt{5}}{\frac{\sqrt{6}}{2}}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
\frac{27\sqrt{5}\times 2}{\sqrt{6}}
Divide 27\sqrt{5} by \frac{\sqrt{6}}{2} by multiplying 27\sqrt{5} by the reciprocal of \frac{\sqrt{6}}{2}.
\frac{27\sqrt{5}\times 2\sqrt{6}}{\left(\sqrt{6}\right)^{2}}
Rationalize the denominator of \frac{27\sqrt{5}\times 2}{\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
\frac{27\sqrt{5}\times 2\sqrt{6}}{6}
The square of \sqrt{6} is 6.
\frac{54\sqrt{5}\sqrt{6}}{6}
Multiply 27 and 2 to get 54.
\frac{54\sqrt{30}}{6}
To multiply \sqrt{5} and \sqrt{6}, multiply the numbers under the square root.
9\sqrt{30}
Divide 54\sqrt{30} by 6 to get 9\sqrt{30}.