Solve 92/3+51/48-1/60

$$9 \frac { 2 } { 3 } + 5 \frac { 1 } { 48 } - \frac { 1 } { 60 }$$

Evaluate

$$\frac{3521}{240}\approx 14.670833333$$

Solution Steps

Multiply 9 and 3 to get 27.

$$\frac{27+2}{3}+\frac{5\times 48+1}{48}-\frac{1}{60}$$

Add 27 and 2 to get 29.

$$\frac{29}{3}+\frac{5\times 48+1}{48}-\frac{1}{60}$$

Multiply 5 and 48 to get 240.

$$\frac{29}{3}+\frac{240+1}{48}-\frac{1}{60}$$

Add 240 and 1 to get 241.

$$\frac{29}{3}+\frac{241}{48}-\frac{1}{60}$$

Least common multiple of 3 and 48 is 48. Convert \frac{29}{3} and \frac{241}{48} to fractions with denominator 48.

$$\frac{464}{48}+\frac{241}{48}-\frac{1}{60}$$

Since \frac{464}{48} and \frac{241}{48} have the same denominator, add them by adding their numerators.

$$\frac{464+241}{48}-\frac{1}{60}$$

Add 464 and 241 to get 705.

$$\frac{705}{48}-\frac{1}{60}$$

Reduce the fraction \frac{705}{48} to lowest terms by extracting and canceling out 3.

$$\frac{235}{16}-\frac{1}{60}$$

Least common multiple of 16 and 60 is 240. Convert \frac{235}{16} and \frac{1}{60} to fractions with denominator 240.

$$\frac{3525}{240}-\frac{4}{240}$$

Since \frac{3525}{240} and \frac{4}{240} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3525-4}{240}$$

Subtract 4 from 3525 to get 3521.

$$\frac{3521}{240}$$

Factor

$$\frac{7 \cdot 503}{2 ^ {4} \cdot 3 \cdot 5} = 14\frac{161}{240} = 14.670833333333333$$