Solve 91/8+24/6+7/10

$$9 \frac { 1 } { 8 } + 2 \frac { 4 } { 6 } + \frac { 7 } { 10 }$$

Evaluate

$$\frac{1499}{120}\approx 12.491666667$$

Solution Steps

Multiply 9 and 8 to get 72.

$$\frac{72+1}{8}+\frac{2\times 6+4}{6}+\frac{7}{10}$$

Add 72 and 1 to get 73.

$$\frac{73}{8}+\frac{2\times 6+4}{6}+\frac{7}{10}$$

Multiply 2 and 6 to get 12.

$$\frac{73}{8}+\frac{12+4}{6}+\frac{7}{10}$$

Add 12 and 4 to get 16.

$$\frac{73}{8}+\frac{16}{6}+\frac{7}{10}$$

Reduce the fraction \frac{16}{6} to lowest terms by extracting and canceling out 2.

$$\frac{73}{8}+\frac{8}{3}+\frac{7}{10}$$

Least common multiple of 8 and 3 is 24. Convert \frac{73}{8} and \frac{8}{3} to fractions with denominator 24.

$$\frac{219}{24}+\frac{64}{24}+\frac{7}{10}$$

Since \frac{219}{24} and \frac{64}{24} have the same denominator, add them by adding their numerators.

$$\frac{219+64}{24}+\frac{7}{10}$$

Add 219 and 64 to get 283.

$$\frac{283}{24}+\frac{7}{10}$$

Least common multiple of 24 and 10 is 120. Convert \frac{283}{24} and \frac{7}{10} to fractions with denominator 120.

$$\frac{1415}{120}+\frac{84}{120}$$

Since \frac{1415}{120} and \frac{84}{120} have the same denominator, add them by adding their numerators.

$$\frac{1415+84}{120}$$

Add 1415 and 84 to get 1499.

$$\frac{1499}{120}$$

Factor

$$\frac{1499}{2 ^ {3} \cdot 3 \cdot 5} = 12\frac{59}{120} = 12.491666666666667$$