Solve 91/10+1/10*7

$$9 \frac { 1 } { 10 } + \frac { 1 } { 10 } \cdot 7$$

Evaluate

$$\frac{49}{5}=9.8$$

Solution Steps

Multiply 9 and 10 to get 90.

$$\frac{90+1}{10}+\frac{1}{10}\times 7$$

Add 90 and 1 to get 91.

$$\frac{91}{10}+\frac{1}{10}\times 7$$

Multiply \frac{1}{10} and 7 to get \frac{7}{10}.

$$\frac{91}{10}+\frac{7}{10}$$

Since \frac{91}{10} and \frac{7}{10} have the same denominator, add them by adding their numerators.

$$\frac{91+7}{10}$$

Add 91 and 7 to get 98.

$$\frac{98}{10}$$

Reduce the fraction \frac{98}{10} to lowest terms by extracting and canceling out 2.

$$\frac{49}{5}$$

Factor

$$\frac{7 ^ {2}}{5} = 9\frac{4}{5} = 9.8$$