Solve 91/frac{1{24}+1/56}

$$9 \frac { 1 } { \frac { 1 } { 24 } + \frac { 1 } { 56 } }$$

Evaluate

$$\frac{756}{5}=151.2$$

Solution Steps

Least common multiple of 24 and 56 is 168. Convert \frac{1}{24} and \frac{1}{56} to fractions with denominator 168.

$$9\times \frac{1}{\frac{7}{168}+\frac{3}{168}}$$

Since \frac{7}{168} and \frac{3}{168} have the same denominator, add them by adding their numerators.

$$9\times \frac{1}{\frac{7+3}{168}}$$

Add 7 and 3 to get 10.

$$9\times \frac{1}{\frac{10}{168}}$$

Reduce the fraction \frac{10}{168} to lowest terms by extracting and canceling out 2.

$$9\times \frac{1}{\frac{5}{84}}$$

Divide 1 by \frac{5}{84} by multiplying 1 by the reciprocal of \frac{5}{84}.

$$9\times 1\times \frac{84}{5}$$

Multiply 1 and \frac{84}{5} to get \frac{84}{5}.

$$9\times \frac{84}{5}$$

Express 9\times \frac{84}{5} as a single fraction.

$$\frac{9\times 84}{5}$$

Multiply 9 and 84 to get 756.

$$\frac{756}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 3 ^ {3} \cdot 7}{5} = 151\frac{1}{5} = 151.2$$