Solve 9div6-4*7+3=

$$9 \div 6 - 4 \times 7 + 3 =$$

Evaluate

$$-\frac{47}{2}=-23.5$$

Solution Steps

Reduce the fraction \frac{9}{6} to lowest terms by extracting and canceling out 3.

$$\frac{3}{2}-4\times 7+3$$

Multiply 4 and 7 to get 28.

$$\frac{3}{2}-28+3$$

Convert 28 to fraction \frac{56}{2}.

$$\frac{3}{2}-\frac{56}{2}+3$$

Since \frac{3}{2} and \frac{56}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-56}{2}+3$$

Subtract 56 from 3 to get -53.

$$-\frac{53}{2}+3$$

Convert 3 to fraction \frac{6}{2}.

$$-\frac{53}{2}+\frac{6}{2}$$

Since -\frac{53}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{-53+6}{2}$$

Add -53 and 6 to get -47.

$$-\frac{47}{2}$$

Factor

$$-\frac{47}{2} = -23\frac{1}{2} = -23.5$$