Solve for f
f=\frac{\left(x^{3}-1\right)^{4}}{9x}
x\neq 0
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9xf=\left(x^{3}-1\right)^{4}
The equation is in standard form.
\frac{9xf}{9x}=\frac{\left(x-1\right)^{4}\left(x^{2}+x+1\right)^{4}}{9x}
Divide both sides by 9x.
f=\frac{\left(x-1\right)^{4}\left(x^{2}+x+1\right)^{4}}{9x}
Dividing by 9x undoes the multiplication by 9x.
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