Solve 9*8^3-8^3=2^x

$$9 \cdot 8 ^ { 3 } - 8 ^ { 3 } = 2 ^ { x }$$

Solve for x

$$x=12$$

Steps Using Definition of Logarithm

Calculate 8 to the power of 3 and get 512.

$$9\times 512-8^{3}=2^{x}$$

Multiply 9 and 512 to get 4608.

$$4608-8^{3}=2^{x}$$

Calculate 8 to the power of 3 and get 512.

$$4608-512=2^{x}$$

Subtract 512 from 4608 to get 4096.

$$4096=2^{x}$$

Swap sides so that all variable terms are on the left hand side.

$$2^{x}=4096$$

Take the logarithm of both sides of the equation.

$$\log(2^{x})=\log(4096)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$x\log(2)=\log(4096)$$

Divide both sides by \log(2).

$$x=\frac{\log(4096)}{\log(2)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{2}\left(4096\right)$$

Solve for x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(2)}+12$$

$$n_{1}\in \mathrm{Z}$$