Solve 9*1-(8-4*3)+9-4*3/8-3*2

$$9 \cdot \frac { 1 - ( 8 - 4 \times 3 ) + 9 - 4 \times 3 } { 8 - 3 \times 2 }$$

Evaluate

$$9$$

Solution Steps

Multiply 4 and 3 to get 12.

$$9\times \frac{1-\left(8-12\right)+9-4\times 3}{8-3\times 2}$$

Subtract 12 from 8 to get -4.

$$9\times \frac{1-\left(-4\right)+9-4\times 3}{8-3\times 2}$$

The opposite of -4 is 4.

$$9\times \frac{1+4+9-4\times 3}{8-3\times 2}$$

Add 1 and 4 to get 5.

$$9\times \frac{5+9-4\times 3}{8-3\times 2}$$

Add 5 and 9 to get 14.

$$9\times \frac{14-4\times 3}{8-3\times 2}$$

Multiply 4 and 3 to get 12.

$$9\times \frac{14-12}{8-3\times 2}$$

Subtract 12 from 14 to get 2.

$$9\times \frac{2}{8-3\times 2}$$

Multiply 3 and 2 to get 6.

$$9\times \frac{2}{8-6}$$

Subtract 6 from 8 to get 2.

$$9\times \frac{2}{2}$$

Divide 2 by 2 to get 1.

$$9\times 1$$

Multiply 9 and 1 to get 9.

$$9$$

Factor

$$3^{2}$$