Solve 9*[3+4*(15+6*a):18]=81

$$9 \cdot [ 3 + 4 \cdot ( 15 + 6 \cdot a ) : 18 ] = 81$$

Solve for a

$$a=2$$

Steps for Solving Linear Equation

Divide both sides by 9.

$$3+\frac{4\left(15+6a\right)}{18}=\frac{81}{9}$$

Divide 81 by 9 to get 9.

$$3+\frac{4\left(15+6a\right)}{18}=9$$

Multiply both sides of the equation by 18.

$$54+4\left(15+6a\right)=162$$

Use the distributive property to multiply 4 by 15+6a.

$$54+60+24a=162$$

Add 54 and 60 to get 114.

$$114+24a=162$$

Subtract 114 from both sides.

$$24a=162-114$$

Subtract 114 from 162 to get 48.

$$24a=48$$

Divide both sides by 24.

$$a=\frac{48}{24}$$

Divide 48 by 24 to get 2.

$$a=2$$