Solve for m
m=3
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9\times 9^{m}=6561
Use the rules of exponents and logarithms to solve the equation.
9^{m}=729
Divide both sides by 9.
\log(9^{m})=\log(729)
Take the logarithm of both sides of the equation.
m\log(9)=\log(729)
The logarithm of a number raised to a power is the power times the logarithm of the number.
m=\frac{\log(729)}{\log(9)}
Divide both sides by \log(9).
m=\log_{9}\left(729\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
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