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Solve for x (complex solution)
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9^{3x-8}=6561
Use the rules of exponents and logarithms to solve the equation.
\log(9^{3x-8})=\log(6561)
Take the logarithm of both sides of the equation.
\left(3x-8\right)\log(9)=\log(6561)
The logarithm of a number raised to a power is the power times the logarithm of the number.
3x-8=\frac{\log(6561)}{\log(9)}
Divide both sides by \log(9).
3x-8=\log_{9}\left(6561\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3x=4-\left(-8\right)
Add 8 to both sides of the equation.
x=\frac{12}{3}
Divide both sides by 3.