Solve 9^2+8^2,7^2+3=

$$9 ^ { 2 } + 8 ^ { 2 } , 7 ^ { 2 } + 3 =$$

Sort

$$52,145$$

Solution Steps

Calculate 9 to the power of 2 and get 81.

$$sort(81+8^{2},7^{2}+3)$$

Calculate 8 to the power of 2 and get 64.

$$sort(81+64,7^{2}+3)$$

Add 81 and 64 to get 145.

$$sort(145,7^{2}+3)$$

Calculate 7 to the power of 2 and get 49.

$$sort(145,49+3)$$

Add 49 and 3 to get 52.

$$sort(145,52)$$

To sort the list, start from a single element 145.

$$145$$

Insert 52 to the appropriate location in the new list.

$$52,145$$

Evaluate

$$145,52$$