Solve 9^2+6g+8

$$9 ^ { 2 } + 6 g + 8$$

Evaluate

$$6g+89$$

Solution Steps

Calculate 9 to the power of 2 and get 81.

$$81+6g+8$$

Add 81 and 8 to get 89.

$$89+6g$$

Differentiate w.r.t. g

$$6$$

Steps Using Derivative Rule for Sum

Calculate 9 to the power of 2 and get 81.

$$\frac{\mathrm{d}}{\mathrm{d}g}(81+6g+8)$$

Add 81 and 8 to get 89.

$$\frac{\mathrm{d}}{\mathrm{d}g}(89+6g)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$6g^{1-1}$$

Subtract 1 from 1.

$$6g^{0}$$

For any term t except 0, t^{0}=1.

$$6\times 1$$

For any term t, t\times 1=t and 1t=t.

$$6$$