Solve 9^-2*3^-2*4^-1=

$$9 ^ { - 2 } \cdot 3 ^ { - 2 } \cdot 4 ^ { - 1 } =$$

Evaluate

$$\frac{1}{2916}\approx 0.000342936$$

Solution Steps

Calculate 9 to the power of -2 and get \frac{1}{81}.

$$\frac{1}{81}\times 3^{-2}\times 4^{-1}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$\frac{1}{81}\times \frac{1}{9}\times 4^{-1}$$

Multiply \frac{1}{81} and \frac{1}{9} to get \frac{1}{729}.

$$\frac{1}{729}\times 4^{-1}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\frac{1}{729}\times \frac{1}{4}$$

Multiply \frac{1}{729} and \frac{1}{4} to get \frac{1}{2916}.

$$\frac{1}{2916}$$

Factor

$$\frac{1}{2 ^ {2} \cdot 3 ^ {6}} = 0.0003429355281207133$$