Solve 9=x^2+10

$$9 = x ^ { 2 } + 10$$

Solve for x (complex solution)

$$x=-i$$

$$x=i$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+10=9$$

Subtract 10 from both sides.

$$x^{2}=9-10$$

Subtract 10 from 9 to get -1.

$$x^{2}=-1$$

The equation is now solved.

$$x=i x=-i$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+10=9$$

Subtract 9 from both sides.

$$x^{2}+10-9=0$$

Subtract 9 from 10 to get 1.

$$x^{2}+1=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4}}{2}$$

Take the square root of -4.

$$x=\frac{0±2i}{2}$$

Now solve the equation x=\frac{0±2i}{2} when ± is plus.

$$x=i$$

Now solve the equation x=\frac{0±2i}{2} when ± is minus.

$$x=-i$$

The equation is now solved.

$$x=i x=-i$$